面试题-08.03 Posted on 2020-07-31 Edited on 2025-02-13 In 程序员面试金典 题目 结果 代码12345678910class Solution { public int findMagicIndex(int[] nums) { for (int i = 0; i < nums.length; i++) { if (nums[i] == i) { return i; } } return -1; }} 复杂度时间复杂度:O(n) 空间复杂度:O(1)